The hypotenuse of a right angle triangle is 15 cm. the sum of the legs of the triangle is 21 cm. Find the legs of the triangle.
How do I solve this?
ps I have to solve this using the quadratic formula
The hypotenuse of a right angle triangle is 15 cm. the sum of the legs of the triangle is 21 cm. Find the legs of the triangle.
How do I solve this?
ps I have to solve this using the quadratic formula
I would figure that by scaling, you can make $\displaystyle \frac{15}{3}=5$ making the hypotenuse 5, then knowing this, and the 3-4-5 rule, you could make the legs, 3 and 4 respectively, then to convert back to the parameters of the problem, you'd multiply back by 3, giving you $\displaystyle 3*3 = 9$ and $\displaystyle 4*3 = 12$ which if added, $\displaystyle 9+12 = 21$ give you the 21 cm stated in the problem.
Let $\displaystyle a$ and $\displaystyle b$ denote the legs of the right triangle, we know that
$\displaystyle a+b=21$
and
$\displaystyle a^2+b^2=225$
Now solve that system of equations
You should get (its in white so you don't have to see it, if you wish to just highlight below)
x=9 and y=12 or y=9 and x=12...they are describing the same triangle