3x^2 - x - 2 = 0
x = 1
Is there another solution to this equation ie another number that can be x?
yes, princess, there is. in fact, quadratics always have two solutions (though there may be a repeated root, but whatever )
note that $\displaystyle 3x^2 - x - 2 = (3x + 2)(x - 1)$
now for that to equal zero, we must have 3x + 2 = 0 or x - 1 = 0. those give you your two solutions