how do i solve:
1)
4 - x
---------- < 0
(x-3)(x+2)
There are three critical points here, x = 4, 3, -2. (Critical points are found where the numerator or denominator are zero.) So the equation is possibly true for the following intervals: (-inf, -2), (-2, 3), (3, 4), and (4, inf). Check each of these possibilities.Originally Posted by bigstarz
-Dan
The method topsuark used is the preferred method. Here is another one.Originally Posted by bigstarz
Whenever you have a faction it is negative when the signs or numerator and denominator do not match (one positive and one negative).
Thus, there are two possibilities
(1)
OR
(2)
Solving (1),
The second inequality,
has solutions,
Combining these solutions together (find their intersection in strict terms) and you have,
Solving (2),
The second inequality,
has solutions,
Combining these solutions together (find their intersection in strict terms) and you have,
(cuz first inequlaity is contained in this one).
Thus,