quadradic equation

**Brooke** · July 26th 2006, 09:29 AM

Solve by using the quadratic formula $x^2-13x+30=0$

**galactus** · July 26th 2006, 11:50 AM

Surely, Brooke, you can use the quadratic formula to solve this yourself.

Please say you can. It's just a matter of plugging and chugging.

That's why the formula is so handy. Just be careful with your signs.

**ThePerfectHacker** · July 26th 2006, 12:26 PM

Originally Posted by Brooke

Solve by using the quadratic formula $x^2-13x+30=0$

Note,
$a=1,b=-13,c=30$
Thus,
$x=\frac{b\pm \sqrt{b^2-4ac} }{2a}$
Thus,
$x=\frac{-13\pm \sqrt{169-4(1)(30)}}{2(1)}$
Thus,
$x=\frac{-13\pm \sqrt{169-120}}{2}$
Thus,
$x=\frac{-13\pm 7}{2}$
Thus,
$x=\frac{-13+7}{2}=-3,x=\frac{-13-7}{2}=-10$

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