Solve by using the quadratic formula $\displaystyle x^2-13x+30=0$

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- Jul 26th 2006, 09:29 AMBrookeUrgent!!!
Solve by using the quadratic formula $\displaystyle x^2-13x+30=0$

- Jul 26th 2006, 11:50 AMgalactus
Surely, Brooke, you can use the quadratic formula to solve this yourself.

Please say you can. It's just a matter of plugging and chugging.

That's why the formula is so handy. Just be careful with your signs. - Jul 26th 2006, 12:26 PMThePerfectHackerQuote:

Originally Posted by**Brooke**

$\displaystyle a=1,b=-13,c=30$

Thus,

$\displaystyle x=\frac{b\pm \sqrt{b^2-4ac} }{2a}$

Thus,

$\displaystyle x=\frac{-13\pm \sqrt{169-4(1)(30)}}{2(1)}$

Thus,

$\displaystyle x=\frac{-13\pm \sqrt{169-120}}{2}$

Thus,

$\displaystyle x=\frac{-13\pm 7}{2}$

Thus,

$\displaystyle x=\frac{-13+7}{2}=-3,x=\frac{-13-7}{2}=-10$