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- Jul 7th 2008, 05:18 PMnae33
(Clapping)

- Jul 7th 2008, 05:36 PMKrizalid
$\displaystyle \begin{aligned}

\frac{4x-2}{x+4}&\le 3 \\

\frac{4x-2}{x+4}-3&\le 0 \\

\frac{4x-2-3x-12}{x+4}&\le 0 \\

\frac{x-14}{x+4}&\le 0.

\end{aligned}$

Can you take it from there? - Jul 7th 2008, 05:51 PMnae33
thank u i just realized i already did this problem and came out the same(Rofl)