You can change this term into:

You are supposed to knowNext:

...

I understand how to get to here:

x^2 -6x +9 = 7

but do not understand getting here:

(x-3)^2 = 7

from this step on however I can solve these.

....... and

That means if you have a sum like the RHS of the formulae which represent a complete square you can write it as a square.

Unfortunately the problem is nearly unreadable ...the problem is with things like this:

3i*(4+5i)^2=3i(16+10i+25i^2)=48i+30i^2+75i^3

(4-5i)^2 (4+5i)^2 (1?)

where do I go from here? what exactly happens to the denominator? will it always cancel completely (did it even do that here?)?

Maybe you are asked to simplify

You have to transform the equation until you have only the unknown to the power of something. Then you want to get the unknown to the power ofAnd Lastly...

Polynomial equations

...

First of all I have no clue what to do when you have afractional exponent:

4x^3/2 - 8 = 0

the book adds 8 then divides by 4, I'm good up to here:

x^3/2= 2

But what did they do to get the 3/2 onto the two like this:

x=2^2/3one. Use the property:

With your problem: