# Math Help - simultaneous problem solving (2

1. ## simultaneous problem solving (2

hey need help here

1- a tent manufacturer produces two models, the Outback and the Bushwalker. From earlier sales records it is known that 20 per cent more of the Outback model is sold than the Bushwalker. A profit of $200 is made on each Outback sold, but$350 is made on each Bush walker. If during the next year a profit of $177 000 is planned, how many of each model must be sold. attempt outback- 20%more and$200p.each
bushwalker- $350p.each so outback is 20/100 + 200x so bush walker is 350y where to form here ? 2- OZ jeans has factories in Mydney and Selbourne. At the Mydney factory fixed costs are$28 000 per month and the cost of producing each pair of jeans is $30. At the selbourne factory, fixed costs are$35200 per month and each pair of jeans costs $24 to produce. during the next month OZ jeans must manufacture 6000 pairs of jeans. Calculate the production order for each factory, if th total manufacturing cost are to be the same. attempt Mydeny= 28,000 p.month +30x Selbourne 35200p.month +24x ...? Thanks for anyone who can help . 2. Originally Posted by white hey need help here 1- a tent manufacturer produces two models, the Outback and the Bushwalker. From earlier sales records it is known that 20 per cent more of the Outback model is sold than the Bushwalker. A profit of$200 is made on each Outback sold, but $350 is made on each Bush walker. If during the next year a profit of$177 000 is planned, how many of each model must be sold.

[snip]
Let X be number of bushwalker and Y be number of outback.

Then X = Y + 20% of Y => X = Y + Y/5 (since 20% is the same as 1/5) => X = 6Y/5.

X = 6Y/5 .... (1)

Profit: 350 X + 200 Y = 177 000 => 35X + 20Y = 17700 => 7X + 4Y = 3540

7X + 4Y = 3540 .... (2)

Solve equations (1) and (2) simultaneously (I suggest using the substitution method).

3. Originally Posted by white
[snip]
2- OZ jeans has factories in Mydney and Selbourne. At the Mydney factory fixed costs are $28 000 per month and the cost of producing each pair of jeans is$30. At the selbourne factory, fixed costs are $35200 per month and each pair of jeans costs$24 to produce. during the next month OZ jeans must manufacture 6000 pairs of jeans. Calculate the production order for each factory, if th total manufacturing cost are to be the same.

attempt
Mydeny= 28,000 p.month +30x
Selbourne 35200p.month +24x
...?

Thanks for anyone who can help .
Let number of jeans at Mydney be M and number of jeans at Selbourne be S.

Total number of jeans: M + S = 6000 ..... (1)

Production costs: (28,000 + 30M) = (35,200 + 24S) => 30M - 24S = 7200 => 5M - 4S = 1200.

5M - 4S = 1200 .... (2)

Solve equations (1) and (2) simultaneously. (I suggest the elimination method).