I was doing okay about these until this one! log6(2x-6) = 2 that first six is a sub...whateveryoucallit. the 2x-6 part is throwing me off. Help?
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Originally Posted by mankvill I was doing okay about these until this one! log6(2x-6) = 2 that first six is a sub...whateveryoucallit. the 2x-6 part is throwing me off. Help? Just do it like you normally would. $\displaystyle log_{6} (2x - 6) = 2$ $\displaystyle (2x - 6) = 6^2 = 36$ $\displaystyle 2x - 6 = 36$ $\displaystyle 2x = 42$ $\displaystyle x = 21$
ah okay i see! Thanks a lot.
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