As an Aerial Porter in the USAF one of my jobs is to load and transfer pallets with cargo from one point to another. If I have one load of pallets that weighs 10,000 lbs and it takes me 2 hours to transfer these to a C-17 with a required 15 min rest every 3 hours how long would it take me to transfer 60,000 lbs?

2. As an Aerial Porter in the USAF one of my jobs is to load and transfer pallets with cargo from one point to another. If I have one load of pallets that weighs 10,000 lbs and it takes me 2 hours to transfer these to a C-17 with a required 15 min rest every 3 hours how long would it take me to transfer 60,000 lbs?

Let's break this problem down a little. First, we will consider the "transfer time." So we multiply 2 hours by 6 (since we will have six loads). This is 12 hours. Now, let's multiply 15 minutes (or a quarter of an hour) by the number of times that 3 hours elapses. In 12 hours, 3 hours elapses 4 times. 4 times 15 minutes is an hour. Therefore, we add an additional hour to 12 which gives us 13 hours. Does this suffice or do you want this presented algebraically?

I hope this helps.
-Andy

3. Originally Posted by ROZZALI
As an Aerial Porter in the USAF one of my jobs is to load and transfer pallets with cargo from one point to another. If I have one load of pallets that weighs 10,000 lbs and it takes me 2 hours to transfer these to a C-17 with a required 15 min rest every 3 hours how long would it take me to transfer 60,000 lbs?
if it takes 2 hours to move 10,000 lbs, it will take 6*2 hours to move 6*10,000 lbs. that is, it will take 12 hours to move them. but we require rest every 3 hours. there are 4 sets of 3 hours in 12 hours, so we will rest 4 times. 4*15 mins = 1 hour. so in all, it will take 13 hours.

EDIT: too late...again