You throw it out as being of second degree in relative error, and soOriginally Posted by OReilly
if the relative errors are relativly small this is negligable in comparison.
Can someone show me the proof that relative error of product of approximant numbers is equal to sum of relative errors of each factors?
I need to show that
I know that
If we divide both sides with we get that
That's how I tried to prove but I don't know what to do with