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Math Help - trigonometry help

  1. #1
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    trigonometry help

    find the value of the 6 trig functions of an angle in standard position whose terminal ray passes through the given point-2,-2)
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Dave1234 View Post
    find the value of the 6 trig functions of an angle in standard position whose terminal ray passes through the given point-2,-2)
    did you draw the diagram? note that you can get a right triangle with these measurements.

    recall that sine = opposite/hypotenuse, cosine = adjacent/hypotenuse, and tangent = opposite/adjacent. that's what SOHCAHTOA is all about.

    then remember that secant = 1/cosine, cosecant = 1/sine and cotangent = 1/tangent

    thus you can find all the trig ratios. note that you will need Pythagoras' theorem to solve for the missing side of the triangle
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  3. #3
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    You got the coordinates (x,y) = (-2, -2). Apply Pythagorean Theorem and find the value of r.

    x^2 + y^2 = r^2

    Where x being the adjacent side, y being the opposite side, and r is the hypotenuse.

    Now that you got the values of x, y, and r, simply replace it in the 6 trigonometric ratios.

    \sin{\theta} = \frac{y}{r}

    \cos{\theta} = \frac{x}{r}

    \tan{\theta} = \frac{y}{x}

    \csc{\theta} = \frac{r}{y}

    \sec{\theta} = \frac{r}{x}

    \cot{\theta} = \frac{x}{y}

    EDIT: Jhev, I had the reply menu open and posted before I knew you already answered him.
    Last edited by Chop Suey; July 8th 2008 at 11:59 AM.
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  4. #4
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    i know that but for some reason my answers aren't working out with the diagram.

    so can you try and show me the 6 trigs on your answer and then i will see where i went wrong does r=2root2
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  5. #5
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    I've just told you how to do it. And yes, you found r correctly.
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