1. ## trigonometry help

find the value of the 6 trig functions of an angle in standard position whose terminal ray passes through the given point-2,-2)

2. Originally Posted by Dave1234
find the value of the 6 trig functions of an angle in standard position whose terminal ray passes through the given point-2,-2)
did you draw the diagram? note that you can get a right triangle with these measurements.

recall that sine = opposite/hypotenuse, cosine = adjacent/hypotenuse, and tangent = opposite/adjacent. that's what SOHCAHTOA is all about.

then remember that secant = 1/cosine, cosecant = 1/sine and cotangent = 1/tangent

thus you can find all the trig ratios. note that you will need Pythagoras' theorem to solve for the missing side of the triangle

3. You got the coordinates (x,y) = (-2, -2). Apply Pythagorean Theorem and find the value of r.

$x^2 + y^2 = r^2$

Where x being the adjacent side, y being the opposite side, and r is the hypotenuse.

Now that you got the values of x, y, and r, simply replace it in the 6 trigonometric ratios.

$\sin{\theta} = \frac{y}{r}$

$\cos{\theta} = \frac{x}{r}$

$\tan{\theta} = \frac{y}{x}$

$\csc{\theta} = \frac{r}{y}$

$\sec{\theta} = \frac{r}{x}$

$\cot{\theta} = \frac{x}{y}$