If m times the mth term of an AP is equal to n times its nth term, find the value of the (m + n)th term. well, after expanding and factorizing I stuck with dividing the whole thing by m-n/...
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Hello, Originally Posted by ice_syncer If m times the mth term of an AP is equal to n times its nth term, find the value of the (m + n)th term. well, after expanding and factorizing I stuck with dividing the whole thing by m-n/... Well, I think you're on the right track ^^ where is the first term of the sequence and r the constant progression. The text says that Factoring by m-n : Conclude ^^
Originally Posted by Moo Hello, Well, I think you're on the right track ^^ where is the first term of the sequence and r the constant progression. The text says that Factoring by m-n : Conclude ^^ Hey uh.... I was taught that the nth term is a1 + (n-1)d = nth term where a1 is the first term of AP
Originally Posted by ice_syncer Hey uh.... I was taught that the nth term is a1 + (n-1)d = nth term where a1 is the first term of AP It's the same. See, if you start at 0 instead of 1, you will have n instead of n-1. Ok, if you want to do this way... Factor by m-n :
Originally Posted by Moo Hello, Well, I think you're on the right track ^^ where is the first term of the sequence and r the constant progression. The text says that Factoring by m-n : Conclude ^^ ok I got it the last factorization step was what helped me, thanks alot!
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