I am stuck on this problem as I think there is no solution can you please tell me if I am right. Solve for x:√x-6 - √x-6 = 36 and problem # 2 Solve for x √x-6√x-6 = 15 Please help me.
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Originally Posted by tricey36 I am stuck on this problem as I think there is no solution can you please tell me if I am right. Solve for x:√x-6 - √x-6 = 36 and problem # 2 Solve for x √x-6√x-6 = 15 Please help me. Is this ? IF so collecting terms we get You must have typed thig swrong For the second one grouping terms we would get Are you sure this is right?
Originally Posted by Mathstud28 Is this ? IF so collecting terms we get You must have typed thig swrong For the second one grouping terms we would get Are you sure this is right? I think the second is [sqrt(x-6)]*[sqrt(x-6)] = 15 So, x -6 = 15 x = 21 ------answer. If that is so, then the first could be sqrt(x-6) -sqrt(x -6) = 36 Which is 0 = 36. There must be really something wrong.
Originally Posted by tricey36 I am stuck on this problem as I think there is no solution can you please tell me if I am right. Solve for x:√x-6 - √x-6 = 36 and problem # 2 Solve for x √x-6√x-6 = 15 As written, these have no solutions (which the others have pointed out): For the second, assuming you wrote it correctly, which has no real solutions.
Originally Posted by tricey36 I am stuck on this problem as I think there is no solution can you please tell me if I am right. Solve for x:√x-6 - √x-6 = 36 and problem # 2 Solve for x √x-6√x-6 = 15 Please help me. In the future, PLEASE use parenthesis! Let me try to read the tea leaves. tricey36, please confirm which of these (if any) you meant. First problem: or (Though this one's just silly.) or Second problem: or These are all I can (reasonably) think of. -Dan
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