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  1. #1
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    radical equations

    I am stuck on this problem as I think there is no solution can you please tell me if I am right.


    Solve for x:√x-6 - √x-6 = 36


    and problem # 2


    Solve for x √x-6√x-6 = 15

    Please help me.
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by tricey36 View Post
    I am stuck on this problem as I think there is no solution can you please tell me if I am right.


    Solve for x:√x-6 - √x-6 = 36


    and problem # 2


    Solve for x √x-6√x-6 = 15

    Please help me.
    Is this

    \sqrt{x}-6-\sqrt{x}-6=36?

    IF so collecting terms we get

    0=36+12

    You must have typed thig swrong

    For the second one grouping terms we would get
    -5\sqrt{x}=27

    Are you sure this is right?
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  3. #3
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    Quote Originally Posted by Mathstud28 View Post
    Is this

    \sqrt{x}-6-\sqrt{x}-6=36?

    IF so collecting terms we get

    0=36+12

    You must have typed thig swrong

    For the second one grouping terms we would get
    -5\sqrt{x}=27

    Are you sure this is right?
    I think the second is
    [sqrt(x-6)]*[sqrt(x-6)] = 15

    So,
    x -6 = 15
    x = 21 ------answer.

    If that is so, then the first could be
    sqrt(x-6) -sqrt(x -6) = 36

    Which is 0 = 36.

    There must be really something wrong.
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  4. #4
    MHF Contributor Reckoner's Avatar
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    Quote Originally Posted by tricey36 View Post
    I am stuck on this problem as I think there is no solution can you please tell me if I am right.

    Solve for x:√x-6 - √x-6 = 36

    and problem # 2

    Solve for x √x-6√x-6 = 15
    As written, these have no solutions (which the others have pointed out):

    \sqrt{x} - 6 - \sqrt x - 6 = 36\Rightarrow 0 = 36

    For the second, assuming you wrote it correctly,

    \sqrt{x} - 6\sqrt x - 6 = 15\Rightarrow -5\sqrt{x} - 6 = 15

    \Rightarrow\sqrt x = -\frac{21}5

    which has no real solutions.
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by tricey36 View Post
    I am stuck on this problem as I think there is no solution can you please tell me if I am right.


    Solve for x:√x-6 - √x-6 = 36


    and problem # 2


    Solve for x √x-6√x-6 = 15

    Please help me.
    In the future, PLEASE use parenthesis!

    Let me try to read the tea leaves. tricey36, please confirm which of these (if any) you meant.
    First problem:
    \sqrt{x} - 6 - \sqrt{x - 6} = 36
    or
    \sqrt{x - 6} - \sqrt{x - 6} = 36
    (Though this one's just silly.)
    or
    \sqrt{x - 6} - \sqrt{x} - 6 = 36

    Second problem:
    \sqrt{x - 6} \sqrt{x - 6} = 15
    or
    \sqrt{x} - 6\sqrt{x} - 6 = 15

    These are all I can (reasonably) think of.

    -Dan
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