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Math Help - Help with solving a log

  1. #1
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    Help with solving a log

    I am stuck on this one. Can someone show me the steps tp solve it. Thanx
    100(1.02)^x/4 =200
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by whiteowl View Post
    I am stuck on this one. Can someone show me the steps tp solve it. Thanx
    100(1.02)^x/4 =200
    100(1.02)^{x/4} = 200 .............divide by 100

    \Rightarrow (1.02)^{x/4} = 2 ..................log both sides

    \Rightarrow \ln (1.02)^{x/4} = \ln 2 ..............apply the rule \log_a (x^n) = n \log_a x

    \Rightarrow \frac x4 \ln 1.02 = \ln 2 ............now solve for x, \ln 1.02 \mbox{ and } \ln 2 are just constants, and can be treated as such
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