I am stuck on this one. Can someone show me the steps tp solve it. Thanx
100(1.02)^x/4 =200
$\displaystyle 100(1.02)^{x/4} = 200$ .............divide by 100
$\displaystyle \Rightarrow (1.02)^{x/4} = 2$ ..................log both sides
$\displaystyle \Rightarrow \ln (1.02)^{x/4} = \ln 2$ ..............apply the rule $\displaystyle \log_a (x^n) = n \log_a x$
$\displaystyle \Rightarrow \frac x4 \ln 1.02 = \ln 2$ ............now solve for $\displaystyle x$, $\displaystyle \ln 1.02 \mbox{ and } \ln 2$ are just constants, and can be treated as such