# Help with solving a log

• June 30th 2008, 01:18 PM
whiteowl
Help with solving a log
I am stuck on this one. Can someone show me the steps tp solve it. Thanx
100(1.02)^x/4 =200
• June 30th 2008, 01:32 PM
Jhevon
Quote:

Originally Posted by whiteowl
I am stuck on this one. Can someone show me the steps tp solve it. Thanx
100(1.02)^x/4 =200

$100(1.02)^{x/4} = 200$ .............divide by 100

$\Rightarrow (1.02)^{x/4} = 2$ ..................log both sides

$\Rightarrow \ln (1.02)^{x/4} = \ln 2$ ..............apply the rule $\log_a (x^n) = n \log_a x$

$\Rightarrow \frac x4 \ln 1.02 = \ln 2$ ............now solve for $x$, $\ln 1.02 \mbox{ and } \ln 2$ are just constants, and can be treated as such