log(x-73)+log(x-88)+2
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log(x-73)+log(x-88)=2 2=log 100 (base is 10) log(x-73)+log(x-88)=log100 as loga+logb=logab therfor log(x-73)(x-88)=log100 or (x-73)(x-88)=100 solving them we get x=93 and x=64 we ignore 64 as its out of domain so the final answer is x=93
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