Originally Posted by
Jhevon haha, stop guessing, and solve it. a would have to be less than 1, of course, otherwise, if you raise it to the 38th power, you would get a number greater than or equal to 1, which is bad, since we have 1/2 on the left hand side
$\displaystyle \frac 12A_0 = A_0a^{38}$
$\displaystyle \Rightarrow \frac 12 = a^{38}$
Now, how would you solve for $\displaystyle a$ here. what must you do to get rid of that 38th power, and be left with just $\displaystyle a$ on the right side?