1. ## Simplify

6/4-14i

a +bi where a and b are real numbers

2. Originally Posted by armygirltiff
6/4-14i

a +bi where a and b are real numbers
$\frac{6}{4-14 \bold{i}}$

$\left(\frac{6}{4-14 \bold{i}}\right) . \left(\frac{4+14 \bold{i}}{4+14 \bold{i}}\right)$

$\frac{6 (4+14 \bold{i})}{(4-14 \bold{i})(4+14 \bold{i})}$

$\frac{24 + 84 \bold{i}}{16 -56\bold{i} + 56\bold{i} -196\bold{i}^2}$

$\frac{24 + 84 \bold{i}}{212}$

$\frac{6}{52} + \frac{21}{53}\bold{i}$

$\implies a=\frac{6}{52}$, $b=\frac{21}{53}$

3. Originally Posted by armygirltiff
6/4-14i

a +bi where a and b are real numbers
$\frac{6}{4} = 1.5$

With the form of $a+bi$, your number has $a = 1.5, b = -14$