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Math Help - 2 Questions!!

  1. #1
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    2 Questions!!

    questions are on attachment!
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Lane
    questions are on attachment!
    1. Solve 3\ e^{4x-5}=2

    Divide through by 3 to get:

    e^{4x-5}=2/3

    Now take natural logs of both sides:

    <br />
4x-5=\log_e(2/3)<br />
.

    Add 5 to both sides:

    <br />
4x=\log_e(2/3)+5<br />
,

    finally divide through by 4:

    <br />
x=(\log_e(2/3)+5)/4 = \log_e \left(\root {1/4}\of {2/3} \right) + 5/4<br />

    RonL
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by Lane
    questions are on attachment!
    2. Find f\circ g, where f(x)=4x-5, and g(x)=x^2-2x+6.

    Now

    <br />
(f \circ g)(x)=f(g(x))=4 g(x)-5= 4(x^2-2x+6)-5=4x^2-8x+19<br />

    RonL
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