b.x/c = d/(1000*(10^(f+log(5/x))))
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Originally Posted by Riley_5000 b.x/c = d/(1000*(10^(f+log(5/x)))) $\displaystyle \frac{bx}{c}=\frac{d}{1000(10^{f\log(5/x)}}$ $\displaystyle bx1000(10^{f\log(5/x)} = dc$ $\displaystyle 10^{f\log(5/x)} = \frac{dc}{1000bx}$ Take the log of both sides $\displaystyle f\log(5/x)\log(10) = \log(\frac{dc}{1000bx})$ Can you finish this?
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