b.x/c = d/(1000*(10^(f+log(5/x))))

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- Jun 24th 2008, 05:45 AMRiley_5000Make x the subject of the formula (:-[)
b.x/c = d/(1000*(10^(f+log(5/x))))

- Jun 24th 2008, 06:06 AMcolby2152
$\displaystyle \frac{bx}{c}=\frac{d}{1000(10^{f\log(5/x)}}$

$\displaystyle bx1000(10^{f\log(5/x)} = dc$

$\displaystyle 10^{f\log(5/x)} = \frac{dc}{1000bx}$

Take the log of both sides

$\displaystyle f\log(5/x)\log(10) = \log(\frac{dc}{1000bx})$

Can you finish this?