Given: 0.352 = -log T How do you isolate T?
Follow Math Help Forum on Facebook and Google+
Originally Posted by dclivefree Given: 0.352 = -log T How do you isolate T? Does $\displaystyle \log(T)=\log_{10}(T)\text{ or }\ln(t)=\log_e(T)$? Either way $\displaystyle -\log(T)=\log\left(\frac{1}{T}\right)$ So $\displaystyle \frac{1}{T}=(e\text{ or }10)^{.352}$
Originally Posted by dclivefree Given: 0.352 = -log T How do you isolate T? Alternatively: 0.352 = -log T => -0.352 = log T => T = a^{-0.352} where a is the base of the logarithm. If the base is 10, then T = 10^{-0.352} = .....
Thank you Mr. Fantastic. You truely are. This is the second time you bailed me out. I am a 44 year old going back to college. I quickly realized that I have much to learn. Thanks again.
View Tag Cloud