I have to make a polynomial function that uses these:
Third-degree, with zeros of -3, -1, and 2, and passes through the point (4, 7)
Hello !
If -3, -1 and 2 are zeros of the polynomial P(x), then x-(-3)=x+3, x+1 and x-2 divide P(x).
But (x+3)(x+1)(x-2) is already a polynomial of degree 3. So P(x) is just proportional to (x+3)(x+1)(x-2).
$\displaystyle P(x)=a(x+3)(x+1)(x-2)$
But we know that $\displaystyle P(4)=7$. Substituting, you can get a