questions are on attachment!!!
Hello, Brooke!
Am I reading the problem wrong?
I don't get any of their answers . . .
2. The number of bison per acre of range in the wild is: $\displaystyle N \:=\:2.1 \times 10^{5-0.004w}$
where $\displaystyle N$ is the number of bison per acre
and $\displaystyle w$ is the average weight of the bison in pounds.
Find the average weight of a bison in a herd that has an average
of seven animals per acre of range.
. . A: 1247 lbs . . B: 1084 lbs . . C: 1134 lbs . . D: 1020 lbs
We are given: $\displaystyle N = 7$
So we have: .$\displaystyle 2.1 \times 10^{5-0.004w}\:=\:7\quad\Rightarrow\quad 10^{5-0.004w}\:=\:\frac{10}{3}$
Then: .$\displaystyle 5-0.004w\:=\:\log\left(\frac{10}{3}\right)\quad \Rightarrow\quad 0.004w\:=\:5 - \log\left(\frac{10}{3}\right) $
Therefore: .$\displaystyle w \;= \;\frac{5 - \log\left(\frac{10}{3}\right)}{0.004}\;=\;1119.280 314$