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Math Help - URGENT HELP!!! pre-test

  1. #1
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    URGENT HELP!!! pre-test

    questions are on attachment!!!
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  2. #2
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    #1 A. Use the property that \log(a)-\log(b)=\log\frac{a}{b}
    Last edited by Jameson; July 19th 2006 at 07:28 AM.
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  3. #3
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    Hello, Brooke!

    Am I reading the problem wrong?
    I don't get any of their answers . . .


    2. The number of bison per acre of range in the wild is: N \:=\:2.1 \times 10^{5-0.004w}
    where N is the number of bison per acre
    and w is the average weight of the bison in pounds.

    Find the average weight of a bison in a herd that has an average
    of seven animals per acre of range.

    . . A: 1247 lbs . . B: 1084 lbs . . C: 1134 lbs . . D: 1020 lbs

    We are given: N = 7

    So we have: . 2.1 \times 10^{5-0.004w}\:=\:7\quad\Rightarrow\quad 10^{5-0.004w}\:=\:\frac{10}{3}

    Then: . 5-0.004w\:=\:\log\left(\frac{10}{3}\right)\quad \Rightarrow\quad 0.004w\:=\:5 - \log\left(\frac{10}{3}\right)

    Therefore: . w \;= \;\frac{5 - \log\left(\frac{10}{3}\right)}{0.004}\;=\;1119.280  314


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  4. #4
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    Quote Originally Posted by Jameson
    #1 A. Use the property that \log(a)-\log(b)=\frac{\log(a)}{\log(b)}
    I'm sorry, Jameson, but I don't think that property holds.

    log(a)-log(b)=log(\frac{a}{b})

    log(a)-log(b)\neq\frac{log(a)}{log(b)}
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  5. #5
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    Quote Originally Posted by galactus
    I'm sorry, Jameson, but I don't think that property holds.

    log(a)-log(b)=log(\frac{a}{b})

    log(a)-log(b)\neq\frac{log(a)}{log(b)}
    You are quite right. It was a Latex typo. Thanks for spotting it.
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