I am bothered with a problem to solve the equation
a3+b3 = 91
a2+b2=61
find the value of and "a" and "b".
where 3 and two is in form of cube and square
Please help me to solve this problem
I am bothered with a problem to solve the equation
a3+b3 = 91
a2+b2=61
find the value of and "a" and "b".
where 3 and two is in form of cube and square
Please help me to solve this problem
put and , then the equations become:
or:
Dividing gives:
rearranging:
Now substitute this back into to get:
Which is a cubic in , solve this, then use these solutions to find the corresponding 's and so the 's and 's. (solution of the cubic will be eased by using Isomorphism's result).
RonL