if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3
Hello, robkitch!
Your English is not quite readable . . .
I'll take a guess at what you meant . . .if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3
We want five cards: one Deuce, one Trey, and three Others.
To get one Deuce, there are: $\displaystyle {4\choose1} = 4$ ways.
To get one Trey, there are: $\displaystyle {4\choose1} = 4$ ways.
To get three Others, there are: $\displaystyle {44\choose3} = 13,244$ ways.
Therefore, there are: .$\displaystyle 4 \times 4 \times 13,244 \:=\:\boxed{211,904\text{ ways}}$