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Math Help - simplify this rational function (logs)?

  1. #1
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    simplify this rational function (logs)?

    How can I simplify this further than it is?

    [8x - {log(base8)x}(8^x)(ln8)] / x(ln8)8^2x
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  2. #2
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    Quote Originally Posted by theowne View Post
    How can I simplify this further than it is?

    [8x - {log(base8)x}(8^x)(ln8)] / x(ln8)8^2x
    You can't do much. Perhaps canceling an 8 from the top and bottom:
    \frac{8x - log_8(x)~8^x~ln(8)}{x~ln(8)~8^{2x}}

    = \frac{x - log_8(x)~8^{x - 1}~ln(8)}{x~ln(8)~8^{2x - 1}}

    -Dan
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    What if the first term was changed from 8x to 8^x? I suppose this would change something?
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