# simplify this rational function (logs)?

• June 15th 2008, 09:13 AM
theowne
simplify this rational function (logs)?
How can I simplify this further than it is?

[8x - {log(base8)x}(8^x)(ln8)] / x(ln8)8^2x
• June 15th 2008, 09:16 AM
topsquark
Quote:

Originally Posted by theowne
How can I simplify this further than it is?

[8x - {log(base8)x}(8^x)(ln8)] / x(ln8)8^2x

You can't do much. Perhaps canceling an 8 from the top and bottom:
$\frac{8x - log_8(x)~8^x~ln(8)}{x~ln(8)~8^{2x}}$

$= \frac{x - log_8(x)~8^{x - 1}~ln(8)}{x~ln(8)~8^{2x - 1}}$

-Dan
• June 16th 2008, 11:52 PM
theowne
What if the first term was changed from 8x to 8^x? I suppose this would change something?