Thread: Re-arranging

I am trying to find voltages in a circuit using KVL and KCL and have got these equations:

1. (x-v)A + (x)B + (x-y)C = 0
2. (y-v)D + (y-x)C + (y)E = 0

I need to re-arrange them to get the form:

1. x(A+B+B) + y(-C) = vA
2. x(-C) + y(D+C+E) = vD

But don't know the process.
I can get the firtst 2 equations from the beginning problem, and given the 2 re-arranged equations I can solve it, but i'm missing a step.Can anyone help?

Originally Posted by hciR

I am trying to find voltages in a circuit using KVL and KCL and have got these equations:

1. (x-v)A + (x)B + (x-y)C = 0
2. (y-v)D + (y-x)C + (y)E = 0

1.
$\displaystyle (x - v)A + (x)B + (x - y)C = 0$

$\displaystyle xA - vA + xB + xC - yC = 0$

$\displaystyle (xA + xB + xC) - yC = vA$

$\displaystyle x(A + B + C) + yC = vA$

The second equation is done in a similar manner.

-Dan

Ah I see now, that's brilliant thanks!