# Re-arranging

• Jun 14th 2008, 04:22 AM
hciR
Re-arranging
I am trying to find voltages in a circuit using KVL and KCL and have got these equations:

1. (x-v)A + (x)B + (x-y)C = 0
2. (y-v)D + (y-x)C + (y)E = 0

I need to re-arrange them to get the form:

1. x(A+B+B) + y(-C) = vA
2. x(-C) + y(D+C+E) = vD

But don't know the process.
I can get the firtst 2 equations from the beginning problem, and given the 2 re-arranged equations I can solve it, but i'm missing a step.Can anyone help?
• Jun 14th 2008, 05:27 AM
topsquark
Quote:

Originally Posted by hciR
I am trying to find voltages in a circuit using KVL and KCL and have got these equations:

1. (x-v)A + (x)B + (x-y)C = 0
2. (y-v)D + (y-x)C + (y)E = 0

1.
\$\displaystyle (x - v)A + (x)B + (x - y)C = 0\$

\$\displaystyle xA - vA + xB + xC - yC = 0\$

\$\displaystyle (xA + xB + xC) - yC = vA\$

\$\displaystyle x(A + B + C) + yC = vA\$

The second equation is done in a similar manner.

-Dan
• Jun 14th 2008, 08:16 AM
hciR
Ah I see now, that's brilliant thanks!