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how do you show your work for 54/y+y=15

Quote: Originally Posted by rambow30 how do you show your work for 54/y+y=15 $\displaystyle \frac{54}{y} + y = 15$ Multiply both sides by y: $\displaystyle 54 + y^2 = 15y$ $\displaystyle y^2 - 15y + 54 = 0$ $\displaystyle (y - 6)(y - 9) = 0$ So y = 6 or 9. -Dan