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Math Help - Quick Help

  1. #1
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    Exclamation Quick Help

    I'm studying and i cant seem to solve a problem. I dont have much time so i don't want you to teach me it instead just answer my question!

    A= 2000
    P= 1000
    i = 0.041
    n= ?

    Equation: A=P(1+i)^n
    Step 1: 2000=1000(1+0.041)^n
    Step 2: 2=(1+0.041)^n
    Step 3: I don't know how to isolate the "n" from here on! Do I square root both sides? Please help asap!
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by Nikola View Post
    I dont have much time so i don't want you to teach me it instead just answer my question!
    Wow!!! Someone woke up on the wrong side of the bed.

    To solve this take the log of both sides (I prefer the natural log ln)

    2=(1+0.041)^n \iff \ln(2)=\ln(1.041)^n

    Now using our log rules we get

    \ln(2)=n\ln(1.041) \iff n=\frac{\ln(2)}{\ln(1.041} \approx 17.25


    I hope your day gets Better
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Nikola View Post
    I'm studying and i cant seem to solve a problem. I dont have much time so i don't want you to teach me it instead just answer my question!
    If a member wants to answer your question in full he/she will. But please remember the best way to get an answer is by learning it, not just seeing the result.

    Cheating is against this forum's policy and will not be tolerated. And your demand to have the answer is insulting. Please do not do this again.

    -Dan
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  4. #4
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    How is that cheating when i need the answer for a question i build to study from? I need an answer not a 2 hour lesson on how to do it. I remember doing this once and it was simple. And im not mad at all i just want the answer instead of a lesson on it. If you wish to call it cheating then thats up to you.
    Anyways i didn't quite understand your log method. Is there any easier way? I think i remember just getting the root or something along those lines. Thanks anyways though im sure i can figure out the first example if your too busy!
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  5. #5
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
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    Quote Originally Posted by Nikola View Post
    How is that cheating when i need the answer for a question i build to study from? I need an answer not a 2 hour lesson on how to do it. I remember doing this once and it was simple. And im not mad at all i just want the answer instead of a lesson on it. If you wish to call it cheating then thats up to you.
    Anyways i didn't quite understand your log method. Is there any easier way? I think i remember just getting the root or something along those lines. Thanks anyways though im sure i can figure out the first example if your too busy!
    The only way to get a variable out of the exponent is with logs.

    Example 2^x=16 since the variable is in the exponent we need logs to solve this problem.

    What I think you are talking about
    Example: x^2=16 This time the variable is in the base so this equation can be solved by the extraction of roots.

    \sqrt{x^2}=\sqrt{16} \iff x= \pm 4

    Best wishes. \emptyset
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  6. #6
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    Thanks again i read up on it and i understand Thanks again for the great help.
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