I have no idea what to do here, can anyone help?:

{ }

I have to find the Domain, Range and Inverse.

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- June 12th 2008, 05:31 PMeh501Functions..
I have no idea what to do here, can anyone help?:

{ }

I have to find the Domain, Range and Inverse. - June 12th 2008, 05:36 PMtopsquark

Domain: Are there any restrictions for x in this expression?

Range: Given the domain, are there any values that y cannot take on?

To find the inverse we must first determine that this is 1 to 1 (which it is.) Then:

Reverse the roles of x and y. (This effectively reflects the function over the line y = x.)

Solve for y:

This is your inverse function.

-Dan - June 12th 2008, 05:39 PMeh501
- June 12th 2008, 05:44 PMtopsquark
Is there any real number that makes undefined or otherwise impossible to calculate? No. Thus the domain is all real numbers.

The situations you need to worry about are functions with vertical asymptotes or that are undefined. For example

is undefined for any values of x that make h(x) = 0. Similarly we can't have any negative numbers or zero in . We also have the case for any "even" radicals that we forbid negative numbers: , or , etc. Since your function contains none of these expressions there is nothing to worry about.

-Dan - June 12th 2008, 05:48 PMeh501
Ok so does that mean that the answer for both the Domain and Range for this question is just "all real #'s"?

- June 12th 2008, 05:55 PMeh501
And i have another question on functions:

"Given the function, , and it's domain, { }, find the range.

What do i do? - June 12th 2008, 05:56 PMtopsquark
- June 12th 2008, 05:58 PMtopsquark
The domain is all values of x from 0 to 4. As this is a linear function the range is easy: just calculate g(x) for the end points of the interval and that is your range.

This is slightly more complicated for a non-linear function. For example, using the same domain,

has a range of all real numbers. The best strategy that I have is to graph the function and visually determine the range.

-Dan - June 12th 2008, 06:06 PMeh501
Im still having trouble finding the range. Do i sub in with anything?

- June 12th 2008, 06:11 PMtopsquark
- June 12th 2008, 06:19 PMeh501
Ohh so it would be { } right?

- June 13th 2008, 03:59 AMtopsquark