Thread: Solve Exponentials

how would you solve for t

2e^-0.05t = e^0.05t

please show all work.
Thanks

$\displaystyle 2e^{-0.05t} = e^{0.05t}$

$\displaystyle 2(e^{0.05t})^{-1} = e^{0.05t}$

$\displaystyle \frac{2}{e^{0.05t}} = e^{0.05t}$

$\displaystyle 2 = e^{0.1t}$

$\displaystyle ln2 = 0.1t$

$\displaystyle t = 10ln2$