how would you solve for t 2e^-0.05t = e^0.05t please show all work. Thanks
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$\displaystyle 2e^{-0.05t} = e^{0.05t}$ $\displaystyle 2(e^{0.05t})^{-1} = e^{0.05t}$ $\displaystyle \frac{2}{e^{0.05t}} = e^{0.05t}$ $\displaystyle 2 = e^{0.1t}$ $\displaystyle ln2 = 0.1t$ $\displaystyle t = 10ln2$
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