i have the following:

b^h = e^ah

i have been told to take the log of each side and show that there is a value of a for every h. Can i do the following?:

ln b^h = ah

but ln b^h = h ln b

so lnb^h = h ln b = ah

cancel h

ln b^h= lb b = a

divide through by ln b

h = a

???? doesnt read right to me.......