i have the following:
b^h = e^ah
i have been told to take the log of each side and show that there is a value of a for every h. Can i do the following?:
ln b^h = ah
but ln b^h = h ln b
so lnb^h = h ln b = ah
cancel h
ln b^h= lb b = a
divide through by ln b
h = a
???? doesnt read right to me.......