1. ## homework due tomorrow.

Solution A is 30% alcohol and solution B is 60% alcohol. How much of each is needed to make 80 liters of a solution that is 45% alcohol?

2. Originally Posted by heather_meaghan
Solution A is 30% alcohol and solution B is 60% alcohol. How much of each is needed to make 80 liters of a solution that is 45% alcohol?

Call the amount of each solution needed $x$ and $y$ (measured in liters). We know that if we combine these two amounts, we should get a total of 80 liters, so
$x + y = 80$.
$0.30x + 0.60y = 0.45\cdot80$.
Solve for $x$ and $y$.