find the exact value of x for which ln(x^2+4x+3)-ln(x^2+x)=4
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Simplify the inside by factoring and canceling the common factor. This should help you right after: where e is the constant 2.718... Then it should be a matter of simple algebra to solve for x.
Originally Posted by outlaw find the exact value of x for which ln(x^2+4x+3)-ln(x^2+x)=4 ln(x^2+4x+3)-ln(x^2+x)=4 ln((x+3)(x+1))-ln(x(x+1))=4 ln(x+3) + ln(x+1)-(ln x + ln(x+1))=4 ln(x+3) -ln x = 4 ln((x+3)/x) = 4 (x+3)/x = e^4 x = 3/(e^4 - 1)
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