Originally Posted by

**cmf0106** As we know the standard form of a quadratic equation is $\displaystyle ax^2 + bx + c = 0$

But when B is equal to 0 in the above it looks like this $\displaystyle ax^2 =c$. However to get the c in the preceding to look like a standard quadratic equation you must add its inverse to the other side.

Take this for example

$\displaystyle x^2 = 49$ Obviously you could just do the $\displaystyle \sqrt49$ to get +- 7. But What if you wanted to put it in general quadratic form?

If I wanted to put it general quadratic form would this be correct?

$\displaystyle x^2 - 49 = 0$

$\displaystyle (x + 7)(x - 7) = 0$

Then just use the multiplicative property of zero to solve both equations and arrive at +- 7?

So in conclusion has my reasoning and calculations been correct up to this point?

Many thanks!