q^2 - m^2 / q-m z + x z+x / is divide by
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Originally Posted by armygirltiff q^2 - m^2 / q-m z + x z+x / is divide by If I have this right you are asking for $\displaystyle \frac{q^2 - m^2}{(z + x)^2} \cdot \frac{1}{q - m}$ $\displaystyle = \frac{(q - m)(q + m)}{(z + x)^2} \cdot \frac{1}{q - m}$ $\displaystyle = \frac{q + m}{(z + x)^2};~q \neq m$ -Dan
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