1. ## help with algerbra equations please

Hi, i new here but im hoping someone can help me with some maths problems.

1. Solve for A, the equation A+5 over 4 + A-6 over 3= 1 over 6 ?

2. The area of a trapezium is given by the formula A= 1 over2 h (a+b), where h is the perpendicualr distance betweeen the two parallel sides and a and b are the lenghts of the parallel sides.
i. Transpose the formula, solving for a

ii. Determine the lenght of a if the area of the trapezium is 17.5cm squared, the perpendicular distance between the two parellel sides is 2.5am and the lenght b is 6cm.

3. Andrew is paid a commision of 12.5% on all the sales he makes. If he earns $4100 in commission in one month, what were his sales for the month? 4. An express train takes 5 and a hafl hours to travel between two cities. If the express train takes only 3/5 of the time an ordinary train takes, how long does it take the ordinary train to travel between the two cities? Thanks whoever can help 2. Originally Posted by binney1975 Hi, i new here but im hoping someone can help me with some maths problems. 1. Solve for A, the equation A+5 over 4 + A-6 over 3= 1 over 6 ? Mr F says: Get rid of the fractions - multiply the whole equation by 12 (the lowest common multiple of 4, 3 and 6). 2. The area of a trapezium is given by the formula A= 1 over2 h (a+b), where h is the perpendicualr distance betweeen the two parallel sides and a and b are the lenghts of the parallel sides. i. Transpose the formula, solving for a Mr F says: Multiply by 2. Divide by h. Subtract b. ii. Determine the lenght of a if the area of the trapezium is 17.5cm squared, the perpendicular distance between the two parellel sides is 2.5am and the lenght b is 6cm. Mr F says: Substitute into the above A = 17.5, h = 2.5, b = 6. 3. Andrew is paid a commision of 12.5% on all the sales he makes. If he earns$4100 in commission in one month, what were his sales for the month?

Mr F says: Solve (12.5/100) x = 4100 => x/8 = 4100 ......

4. An express train takes 5 and a hafl hours to travel between two cities. If the express train takes only 3/5 of the time an ordinary train takes, how long does it take the ordinary train to travel between the two cities?

Mr F says: Solve $\displaystyle {\color{red}\frac{3}{5} \, x = 5 \frac{1}{2} \Rightarrow \frac{3x}{5} = \frac{11}{2}}$. I'd suggest first multiplying through by 10 (the lowest common multiple of 5 and 10).

Thanks whoever can help
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3. Is anybody able to help me with these step by step, showing work and answers. thankyou Binney1975

4. Originally Posted by binney1975
Is anybody able to help me with these step by step, showing work and answers. thankyou Binney1975
You need to show what you've done and where you're stuck.