Originally Posted by

**cmf0106** Actually one last question I forgot to ask yesterday the problem reads

$\displaystyle x + 8 = \frac{3}{2}x - \frac{1}{2}$

Which leads to

$\displaystyle

x= \frac{3}{2}x -8\frac{1}{2}

$

I am not certain how the "$\displaystyle -8\frac{1}{2}$" is created exactly. The RHS reads $\displaystyle \frac{3}{2}x - \frac{1}{2} - 8$ So I assume you can just do (once you subtract 8 from both sides in the first equation displayed) "$\displaystyle -\frac{1}{2} - 8$" which in a calculator = -8.5 or $\displaystyle 8\frac{1}{2}$

Could some one please clarify, thanks.