# Math Help - rational fraction

1. ## please help

Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8

2. Originally Posted by bobby77
Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
Denominator of fraction cannot be zero.
$b^2 - 2b -8 = (b-4)(b+2)$

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