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Thread: rational fraction

  1. July 7th 2006, 10:07 PM #1
    bobby77
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    please help

    Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
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  2. July 7th 2006, 10:30 PM #2
    malaygoel
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    Quote Originally Posted by bobby77
    Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
    Denominator of fraction cannot be zero.
    b^2 - 2b -8 = (b-4)(b+2)

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