Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
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Originally Posted by bobby77 Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8 Denominator of fraction cannot be zero. $\displaystyle b^2 - 2b -8 = (b-4)(b+2)$ Keep Smiling Malay
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