# rational fraction

• July 7th 2006, 10:07 PM
bobby77
Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
• July 7th 2006, 10:30 PM
malaygoel
Quote:

Originally Posted by bobby77
Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8

Denominator of fraction cannot be zero.
$b^2 - 2b -8 = (b-4)(b+2)$

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Malay