Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8

Printable View

- Jul 7th 2006, 10:07 PMbobby77please help
Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8

- Jul 7th 2006, 10:30 PMmalaygoelQuote:

Originally Posted by**bobby77**

$\displaystyle b^2 - 2b -8 = (b-4)(b+2)$

Keep Smiling

Malay