[(y-1)/ (y^2 - 3y - 10)] - [(2y) / (y^2 + 2y - 35)] Simplify. Please show me how you did it step by step. Thank you so much!!
$\displaystyle \frac{y-1}{y^2-3y-10}-\frac{2y}{y^2+2y-35}$
$\displaystyle \frac{y-1}{(y-5)(y+2)}-\frac{2y}{(y+7)(y-5)}$
$\displaystyle LCD=(y-5)(y+2)(y+7)$
$\displaystyle \frac{(y-1)(y+7)}{(y-5)(y+2)(y+7)}-\frac{2y(y+2)}{(y-5)(y+2)(y+7)}$
$\displaystyle \frac{(y-1)(y+7)-2y(y+2)}{(y-5)(y+2)(y+7)}$
$\displaystyle \frac{y^2+6y-7-2y^2-4y}{(y-5)(y+2)(y+7)}$
$\displaystyle \frac{-y^2+2y-7}{(y-5)(y+2)(y+7)}$