# Thread: Can somebody help me with algebra 2?

1. ## Can somebody help me with algebra 2?

[(y-1)/ (y^2 - 3y - 10)] - [(2y) / (y^2 + 2y - 35)] Simplify. Please show me how you did it step by step. Thank you so much!!

2. Originally Posted by gnarlycarly227
[(y-1)/ (y^2 - 3y - 10)] - [(2y) / (y^2 + 2y - 35)] Simplify. Please show me how you did it step by step. Thank you so much!!
(y-1)/((y-5)(y+2)) - 2y/((y-5)(y+7))

((y-1)(y+7))/((y-5)(y+2)(y+7)) - 2y(y+2)/((y-5)(y+2)(y+7))

(y^2 + 6y - 7)/((y-5)(y+2)(y+7)) - (4y^2 + 4y)/((y-5)(y+2)(y+7))

(-3y^2 + 2y - 7)/((y-5)(y+2)(y+7))

3. Originally Posted by sean.1986
(y-1)/((y-5)(y+2)) - 2y/((y-5)(y+7))

((y-1)(y+7))/((y-5)(y+2)(y+7)) - 2y(y+2)/((y-5)(y+2)(y+7))

(y^2 + 6y - 7)/((y-5)(y+2)(y+7)) - (4y^2 + 4y)/((y-5)(y+2)(y+7))

(-3y^2 + 2y - 7)/((y-5)(y+2)(y+7))

$\displaystyle \frac{y-1}{y^2-3y-10}-\frac{2y}{y^2+2y-35}$

$\displaystyle \frac{y-1}{(y-5)(y+2)}-\frac{2y}{(y+7)(y-5)}$

$\displaystyle LCD=(y-5)(y+2)(y+7)$

$\displaystyle \frac{(y-1)(y+7)}{(y-5)(y+2)(y+7)}-\frac{2y(y+2)}{(y-5)(y+2)(y+7)}$

$\displaystyle \frac{(y-1)(y+7)-2y(y+2)}{(y-5)(y+2)(y+7)}$

$\displaystyle \frac{y^2+6y-7-2y^2-4y}{(y-5)(y+2)(y+7)}$

$\displaystyle \frac{-y^2+2y-7}{(y-5)(y+2)(y+7)}$

4. Oops! Seems simple multiplication is beyond me :P

Thought the final answer looked a bit iffy.