5. [12x/ (5xy^4)] - [9y^2/(15x^3y^2)] 6. [6/(x+2)] + 11/ (x-7)
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6. [6/(x+2)] + 11/ (x-7) We find the LCD of the two fractions and that is (x+2)(x-7) So now we build the fraction to had the LCD
[12x/ (5xy^4)] - [9y^2/(15x^3y^2)] LCD = 15 x^3 y^4 =[12x (3 x ^2) / 15 x^3 y^4] - [9y^2 (y^2) / 15 x^3 y ^4] =[36 x^3 / 15x^3y^4] - [9y^4 / 15x^3y^4] = 36x^3 - 9y^4 / 15x^3y^4
Originally Posted by AlgebraAnswers [12x/ (5xy^4)] - [9y^2/(15x^3y^2)] LCD = 15 x^3 y^4 =[12x (3 x ^2) / 15 x^3 y^4] - [9y^2 (y^2) / 15 x^3 y ^4] =[36 x^3 / 15x^3y^4] - [9y^4 / 15x^3y^4] = 36x^3 - 9y^4 / 15x^3y^4 This can be simplified to
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