[12x/5xy^4] - [9y^2/15x^3 y^2
Please show me how to do it step by step I'm so confused.
Thanks so much!

2. Originally Posted by gnarlycarly227
[12x/5xy^4] - [9y^2/15x^3 y^2
Please show me how to do it step by step I'm so confused.
Thanks so much!
I think this is what you want to simplify...

$\frac{12x}{5xy^4}-\frac{9y^2}{15x^3y^2}$

so we find the LCD is $15x^3y^4$

so we build each of the fractions. So we multiply the first one by $3x^2$ and the second by $y^2$ to get

$\frac{12x}{5xy^4}\frac{3x^2}{3x^2}-\frac{9y^2}{15x^3y^2}\frac{y^2}{y^2}=\frac{36x^3-9y^4}{15x^3y^4}=\frac{9(4x^3-y^4)}{12x^3y^2}=\frac{3(4x^3-y^4)}{4x^3y^2}$

I hope this helps.

Good luck.