Please show all work! Thank you sooo much! (Nod)

7. [(y-1) / y^2 - 3y - 10)] - [(2y)/ y^2 + 2y - 35)]

8. [(5/3c) + 7/ 2v)] / [(c/6) - (3/cv)]

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- Jun 1st 2008, 10:48 AMgnarlycarly227Simply each expression. Show all work. Please help!
Please show all work! Thank you sooo much! (Nod)

7. [(y-1) / y^2 - 3y - 10)] - [(2y)/ y^2 + 2y - 35)]

8. [(5/3c) + 7/ 2v)] / [(c/6) - (3/cv)] - Jun 1st 2008, 12:31 PMmasters
- Jun 1st 2008, 01:47 PMgnarlycarly227
yes you do! please help me solve it! how'd you do that?

- Jun 1st 2008, 01:55 PMMoo
Hello !

For the first one, notice that $\displaystyle y^2-3y-10=(y-5)(y+2)$ and $\displaystyle y^2+2y-35=(y+7)(y-5)$

Therefore, the least common multiple of the denominator is $\displaystyle (y-5)(y+7)(y+2)$

Does it help you go through the problem a little more ? - Jun 2nd 2008, 10:00 AMmasters
Already asked and answered here: http://www.mathhelpforum.com/math-he...gebra-2-a.html