1. ## Factoring Special Products

x3y3 + z3

5x3 + 40y6

8y3 - 27

We are suppose to do these but there don't explained how to do this

2. Hello,

Rewrite all this stuff :
Originally Posted by frow4
x3y3 + z3
$=(xy)^3+z^3$

5x3 + 40y6
$=5(x^3+8y^6)=5(x^3+(2y^2)^3)$, because $y^6=y^{2 \cdot 3}=(y^2)^3$

8y3 - 27
$=(2y)^3+(-3)^3$

Now, there is a formula that would help :

$a^3+b^3=(a+b)(a^2-ab+b^2)$