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Math Help - Factoring Special Products

  1. #1
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    Factoring Special Products

    x3y3 + z3


    5x3 + 40y6

    8y3 - 27

    We are suppose to do these but there don't explained how to do this
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  2. #2
    Moo
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    Hello,

    Rewrite all this stuff :
    Quote Originally Posted by frow4 View Post
    x3y3 + z3
    =(xy)^3+z^3

    5x3 + 40y6
    =5(x^3+8y^6)=5(x^3+(2y^2)^3), because y^6=y^{2 \cdot 3}=(y^2)^3

    8y3 - 27
    =(2y)^3+(-3)^3



    Now, there is a formula that would help :

    a^3+b^3=(a+b)(a^2-ab+b^2)
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