How to do this following "Induction sum"?
n
SUM (-1/2)^j = (2^n+1 + (-1)^n)/ 3. 2^n
j=0
How do we remove the "summation" sign here? Also, how to go about proving it by using "induction"?
Thanks for you reply!
I assumed the equality was true for .
Yes, you have to write the code for each formula. See this thread.Also, how to get the symbols like you are using? Do we have to write the code for that?
I did this so that the two fractions share the same denominator.
As , we choose as the common denominator. To make appear at the denominator of the first fraction, we multiply it by . For a similar reason, we multiply the second fraction by .
Otherwise, one can do this as follows :